A motorcycle moving with a speed of 5m/s is subjected to an acceleration of 0.2m/s^2. calculate the speed of the motor cycle after 10 second and the distance travelled in this time.
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HOLA!!!
______________
HERE YOUR ANSWER IS
GIVEN
Initial velocity ( u) = 5ms^-1
Acceleration (a) = 0.2ms^-2
time (t) = 10s
distance (s) = ?
SOLUTION
we know a kinematical equation
v = u+at
= 5+ 0.2 (10)
v = (5 +2)ms^-1
therefore v = 7ms^-1
another kinematical equation
s = ut + 1/2 at^2
= 5 (10) + 1/2 (0.2)(10)^2
= 50 + 0.1 (100)
= 50 + 10
s = 60m
HOPE IT HELPS YOU :)
______________
HERE YOUR ANSWER IS
GIVEN
Initial velocity ( u) = 5ms^-1
Acceleration (a) = 0.2ms^-2
time (t) = 10s
distance (s) = ?
SOLUTION
we know a kinematical equation
v = u+at
= 5+ 0.2 (10)
v = (5 +2)ms^-1
therefore v = 7ms^-1
another kinematical equation
s = ut + 1/2 at^2
= 5 (10) + 1/2 (0.2)(10)^2
= 50 + 0.1 (100)
= 50 + 10
s = 60m
HOPE IT HELPS YOU :)
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