Question

a body is projected obliquely from the ground so that its horizontal range is maximum if the change in its linear momentum as it moves from half the maximum height to maximum height is p the change in its linear momentum as it travels from the point of projection to landing point on the ground will be

Answer 1

As there is no gravitational force in horizontal direction so ucos30=30×√3/2=25.7m/s, will remain same.

But as there is gravitational force in vertical direction so vertical component will change

And here initial u=usin30=30×1/2=15m/s

v=u+a×t

v= 15+(-10×1.5)=0

So after 1.5 second of flight object will be parallel to horizontal so angle will be 0° will horizontal.