Question

A body is projected up a 45° rough incline. If the
coefficient of friction is 0.5, then the retardation
the block is





plz
​

Answer 1

ANSWER

AS THE BODY IS MOVING UP THE INCLINE SO THE COMPONENT OF GRAVITY ALONG THE PLANE AND THE RETARDATION DUE TO FRICTION RETARDING THE MOTION....{∆}

$retardation \: due \: to \: friction \\ is \: given \: below..... \\ \\ f = \gamma g \\ \\ where \: \gamma \: is \: the \: coefficient \: of \: friction \\ \\ retardation \: by \: gravity = g \sin(45) \\ \\ total \: retardation = g \sin(45) + \gamma g \\ retardation = \frac{10}{ \sqrt{2} } + 0.5 \times 10 \\ retardation = 5 \sqrt{2} + 5 \\ total \: retardation = 5(1 + \sqrt{2} )$