Question

a body is projected up with an initial velocity of 10 metre per second it will return to its starting point after​

Answer 1

Explanation:

Solution:

According to equation of motion,

v = u-gt

when the body reaches its highest point, velocity becomes zero. Thus,

u = gt

t = u/g

t = 50 m/s / 9.8 m/s^2

t = 5.10 s

Time to reach the maximum height is 5.10 seconds.

The reverse motion is also takes the same time interval. Thus, t = 5.10 s + 5.10 s = 10.20 s