Question

A body is projected up with an initial velocity u m/s. It goes up to a height h metres in t seconds time. Then it comes back at the point of projection. Considering negligible air resistance, which of the following statement is true? *​

Answer 1

Hello,

Tho your question seems to be incomplete, I'll write an explanation for you, hope this helps :)

Vertical Projectiles.

In the above case, a body is projected up with an initial velocity u m/s .

It takes time t to go up to the height of h meter.

While going upward, the acceleration of the body is in negative direction due to the gravitational force of attraction, which we denote by small 'g'.

Since there is no external force, (air resistance),

If we want to calculate time taken for the body to cover h meters up, we can simply find it by applying Equations of Motion.

$v = u + at$

where,

where, v = final velocity

where, v = final velocity u = initial velocity

where, v = final velocity u = initial velocitya = acceleration

At the highest point of motion, the velocity becomes 0.

Therefore,

$0 = u + ( - g)t \\ = > gt = u \\ = > t = ( \frac{u}{g} )$

When the body comes back, it will again take t time to come to its initial position.

So, for the while journey, the body takes 2t time in total.

Hope this helps :))