An object moving with 6 metre per second execute an acceleration 2 metre per second square in next 3 seconds .how much distance it covered?
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Explanation:
u = 6 m/s
a = 2 m/s^2
find distance after 3 secs
S = ut+1/2 at^2
S = 6(3) + 1/2 (2)(9)
S = 18 + 9
S = 27 m
so it will cover 27 m after 3 secs
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