ABCD is a parallelogram. If <A=125° and <BCE=56°. Find x, y, z
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20
Given,
ABCD is a parallelogram.
∠A = 125°
∠BCZ = 56°
To Find
x, y and z.
Proof
For 'X'
x+ 125° = 180° [Co - Interior Angles]
x = 180° - 125°
x = 55°
For 'Y'
A = ∠C [Opp. angles of a parallelogram are equal]
125° = y + 56°
125° - 56° = y
y = 69°
For 'Z'
ADCZ is a quadrilateral.
∠A + x + y + z = 360°
25° + 55° + 69° + z = 360°
24° + z = 360°
z = 360° - 249°
z = 111°
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3
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