Question

a body is projected upward a velocity of 29.4m/s calculate
i) the maximum height attained
ii) the time taken to reach maximum height. (g=9.8m/s^2)

Answer 1

your answer is given by abhishek

Answer 2

s=(v^2-u^2)/2a
s={0^2-(29.4)^2}/2*(-9.8)
s=44.1
I) 44.1m(ans)
v=u+at
t=(v-u)/a
t=-29.4/-9.8
t=3
2) 3m/s^2 (ans)