Question

A body is projected upward with a velocity of 20 m/s,then the time taken to reach the highest point is

Answer 1

Here,v=0        (it stops at the highest point)

         u=20m/s(given)

         a=  -10     (it is constant and in opposite direction)

v=u+at

0=20-10t

10t=20

t=2 sec

#HOPE IT HELPS#

Answer 2

✴️✴️✴️Here is your answer ⬇️⬇️⬇️

Here we have to use equation of motion-

concept:-$\red{At\:Heighest\:point\:the\:velocity\:of\:the\:object\:becomes\:zero}$

$v = u - gt \\ taking \: + ve \: drection \: as \: upward \\ 0 = 20 - gt \\ - 20 = - 10t \\ t = 2seconds$
Here , [g=10m/s^2]