Question

A body is projected upward with a velocity of 98 m/s find
A) it's velocity at a height 196m from the point of projection

Answer 1

Given,

u = 98 m/s; a = - 9.8 m/s^2; s = 196 m; v = (?)

Then, we know,

2as = v^2 - u^2

=) -19.6 × 196 = v^2 - 9604

=) - 3841.6 + 9604 = v^2

=) v = root 5762.4

=) v = 75.91 m/s (approx.)

HOPE THIS COULD HELP!!!

Answer 2

Answer:

A body A is launched into the air at  98 $ms^{-1}$. A second body B is launched upward with the same velocity after 4 seconds. After then, both bodies will meet 12 s.

Explanation:

What is meant by velocity?

• The most important metric for determining an object's position and rate of movement is its velocity.

• The distance that an object travels in a given amount of time can be used to define it. The object's displacement in a unit of time is referred to as velocity.

• The speed at which something moves in a specific direction is known as its velocity.

• As an illustration, think of the speed of a car driving north on a highway or the speed at which a rocket takes off. Because the velocity vector is scalar, it always has the same absolute value magnitude as the motion's speed.

Therefore,

Let t be the moment of the body A's flight when they cross paths.

The body B's flight time will then be (t-4) seconds.

Given that both bodies would be equally displaced from the ground, As a result, where h1 is the displacement of body A and h2 is the displacement of body B, h1 = h2.

Using the laws of motion

$& \mathrm{h}=\mathrm{ut}-\frac{1}{2} \mathrm{gt}^2$

$& \mathrm{~h}_1=98 \mathrm{t}-\frac{1}{2} \mathrm{gt}^2 \text { and } \mathrm{h}_2=98(\mathrm{t}-4)-\frac{1}{2} \mathrm{~g}(\mathrm{t}-4)^2 \text { and since } \mathrm{h}_1=\mathrm{h}_2$

$& \therefore 98 \mathrm{t}-\frac{1}{2} g \mathrm{t}^2=98(\mathrm{t}-4)-\frac{1}{2} \mathrm{~g}(\mathrm{t}-4)^2$

We obtain t = 12 seconds after solving.

The complete question is:

A body A is projected upwards with a velocity of 98 $ms^{-1}$ After 4 seconds, a second body B is projected upwards with the same velocity. Both the bodies will meet after

To learn more about velocity, refer to:

https://brainly.in/question/1767797

https://brainly.in/question/448356

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