A train X speeding with 120 kmph crosses another train Y, running in the same direction, in 2 minutes. If the lengths of trains X and Y be 100m and 200m respectively, what is speed of train Y(in kmph)?
a. 111
b. 123
c. 127
d. 129
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Answers
Answered by
17
speed = distance / time
s1 -s2 = x+y/t
120-s2 = 100+200/ 2×60
120-s2 =300/120
120-s2 = 5/2
120-s2 = 5/2 × 18/5
120-s2 =9
s2 = 120-9
s2 =111 kmph is answer
option a is answer obtained
hope it helps you friend
s1 -s2 = x+y/t
120-s2 = 100+200/ 2×60
120-s2 =300/120
120-s2 = 5/2
120-s2 = 5/2 × 18/5
120-s2 =9
s2 = 120-9
s2 =111 kmph is answer
option a is answer obtained
hope it helps you friend
bhargav406:
yes as they are moving in same direction speeds should be subtracted
you took s1-s2 which implies s1>s2.How you concluded s1 is the given speed and s2 speed to be found out
s1 > s2 how
s1 is greater than s2
that's what I founded I finded s2 which we have to find by the question
they asked only s2 speed
i didn't get it
s2 can be greater than 120 which we don't know till we solve
then how you took 120-s2
why not s2-120
Answered by
0
Answer:
The speed of train Y is 111 km/hr. [Option(a)]
Step-by-step explanation:
Given Speed of train X is 120 km/hr and Time is 2 minutes.
Length of X is 100 m and length of Y is 200 m.
Let the speed of train Y be V km\hr
Speed of X relative to Y=(120-V)km/hr
= [(120 − V) ] m/sec
= (600-5V) /18 m/sec
Total distance covered = (200+100)= 300 m
∴
→ V = = 111
∴ V= 111 km/hr
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