Question

a body is projected vertically up with velocity 'u' .its velocity at half its maximum height is

Answer 1

initial velocity = u
maximun height = u^2/2g
so velocity at maximum height...
v^2 =u^2-2gh
=u^2 -2g× u^2/2g×2
=u^2 - u^2/2
=u^2/2
v = root u^2/2
v =u/root 2...ans...

Answer 2

answer is

$\frac{u}{ \sqrt{2} }$

it may help you