Question

A body is projected vertically upward with a velocity of 30 m/s. a. How high will it rise? b. For how long will it continue to rise

Answer 1

Answer:

The body will stay in air for 6 seconds.

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.It is accelerating at the rate of a=-10m/sec^2 (gravity).

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.It is accelerating at the rate of a=-10m/sec^2 (gravity).Now just before it starts falling, at the highest point, it's velocity v=0m/sec.

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.It is accelerating at the rate of a=-10m/sec^2 (gravity).Now just before it starts falling, at the highest point, it's velocity v=0m/sec.Substitute the values of u, v and a in

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.It is accelerating at the rate of a=-10m/sec^2 (gravity).Now just before it starts falling, at the highest point, it's velocity v=0m/sec.Substitute the values of u, v and a inv = u + at

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.It is accelerating at the rate of a=-10m/sec^2 (gravity).Now just before it starts falling, at the highest point, it's velocity v=0m/sec.Substitute the values of u, v and a inv = u + atYou get

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.It is accelerating at the rate of a=-10m/sec^2 (gravity).Now just before it starts falling, at the highest point, it's velocity v=0m/sec.Substitute the values of u, v and a inv = u + atYou get0 = 30 + (-10)t

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.It is accelerating at the rate of a=-10m/sec^2 (gravity).Now just before it starts falling, at the highest point, it's velocity v=0m/sec.Substitute the values of u, v and a inv = u + atYou get0 = 30 + (-10)t0 = 30 — 10t

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.It is accelerating at the rate of a=-10m/sec^2 (gravity).Now just before it starts falling, at the highest point, it's velocity v=0m/sec.Substitute the values of u, v and a inv = u + atYou get0 = 30 + (-10)t0 = 30 — 10tt = -30 ÷ (-10)

The body will stay in air for 6 seconds.When the body is thrown upwards at u=30m/sec.It is accelerating at the rate of a=-10m/sec^2 (gravity).Now just before it starts falling, at the highest point, it's velocity v=0m/sec.Substitute the values of u, v and a inv = u + atYou get0 = 30 + (-10)t0 = 30 — 10tt = -30 ÷ (-10)t = 6 sec

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