A body is projected vertically upward with speed 40 m/s . the distance travelled by body in the last second of upward journey is what ( g= 9.8 m/s and neglect eff8 of air resistance)
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Total distance travelled by body = H
Distance travelled by body in last second = d
H = u^2 / (2g)
= 40^2 / (2 * 9.8)
= 1600 / 19.6 m
= 81.63 m
Time taken by body to reach height H is sqrt(2H/g)
= sqrt(2 * 81.63 / 9.8)
= 4.08 seconds
Use equation of motion...,
S = ut + 0.5at^2
H - d = 40*(t - 1) - 0.5g(t - 1)^2
81.63 - d = 40 * (4.08 - 1) - 0.5*9.8*(4.08 - 1)^2
81.63 - d = 76.71
d = 81.63 - 76.71
d = 4.9 m
Thankyou
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