Question

a body is projected verticaly up with velocity 20ms^-1 from a point. the velocity of the same point in its return journey is​

Answer 1

Answer:

-20m/s

Explanation:

let v be 0

=> 0=u+at

      = 20 -10t                           (g=10m/s^2)

  =>10t=20

   => t=2sec

now after 2sec let u be 0

=> v=u+at

=> v=0-10(2)                             (g=10m/s^2)

=>v= -20m/s