Physics, asked by tejaswinidas7799, 1 year ago

A body is projected with a velocity 40m/s at an angle 30 degree with horizontal range find the time of flight and maximum height

Answers

Answered by birajdarabhilasha07
8

Answer:

given:u=40m/s angle=30

time of flight=2u sin theta/g

=2 x40 x  sin30/10

=2 x40 x 1/2 /10

t=4s

H(max)=u2/2g

=40 x 40 /20

H=80m

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