A body is projected with a velocity 40m/s at an angle 30 degree with horizontal range find the time of flight and maximum height
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Answer:
given:u=40m/s angle=30
time of flight=2u sin theta/g
=2 x40 x sin30/10
=2 x40 x 1/2 /10
t=4s
H(max)=u2/2g
=40 x 40 /20
H=80m
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