Physics, asked by chyawan938, 1 year ago

A body is projected with a velocity u so that the horizontal range is twice the maximum height. Then the maximum height is

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Answered by vishagh

11

Let the velocity be u, range be R and maximum height be H max
We knw R=u²/g.
R=2×Hmax
Hmax=R/2=u²/2g

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