Question

a body is projected with a velocity v=3i^+4i^ m/s.the maximum height attained by the body is take g=10 meter per second square.

Answer 1

Question:

A body is projected with a velocity v=3i^+4i^ m/s.the maximum height attained by the body is

(take g =10 m/s^2 )

a)0.8m

b)1.6m

c)3m

d)5m

Answer:

a) 0.8 m

Answer 2

Answer:

The maximum height attained by the body is 0.8m.

Explanation:

The velocity with which the body is projected is given as,

$v=3\hat{i}+4\hat{j}m/s$       (1)

where v includes the velocity both in x-direction and y-direction i.e.

$v_x=3m/s$        (2)

$v_y=4m/s$        (3)

And the maximum height is given as,

$H=\frac{v^2_y}{2g}$            (4)

H=maximum height the body attains

vy=velocity along y-direction

g=acceleration due to gravity which is given as 10m/s²         (constant)

By substituting the required values in equation (4) we get;

$H=\frac{(4)^2}{2\times 10}=\frac{8}{10}=0.8m$

Hence, the maximum height attained by the body is 0.8m.