Question

A body is projected with an initial velocity 20 m/s at an angle of 30 with the horizontal
Calculate maximum height

Answer 1

Here u=30ms−1, Angle of projection, θ=90−30=60∘

Maximum height,

H=2gu2sin2θ​=2×10302sin260∘​=20900​×43​=4135​m

Time of flight, T=g2usinθ​=102×30×sin60∘​=33

​s

Horizontal range = R=gu2sin2θ​=1030×30×2sin60∘cos60∘​=453

​m

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