Question

A body is projected with an initial
velocity of 58.8 m/s at angle 60° with
the vertical. The vertical component
of velocity after 2 sec is​

Answer 1

Answer:

V=60 m/s at 30

∘

(i) U

x

=60 cos 30

∘

i

^

(constant)

U

y

=60sin 30

∘

j

^

U=30

3

i

^

+30

j

^

→ Option C

(iii) V

y

after, 3 second

V

y

=U

y

+gt=30−10×3=0

So

V=30

3

i

^

+O

j

^

→ Option D (after 3 second)

(iii) Displacement is x after 2 second :-

S

x

=U

x

t=30

3

×2=60

3

i

^

Displacement is y :-

S

y

=U

y

t+

2

1

gt

2

=30×2−

2

1

×10×4=40

j

^

S=60

3

i

^

+40

j

^

→ Option a (After 2 second)

(iv) V

y

after, 2 second

v

y

=U

y

+gt=30−10×2=10sec

V=30

3

i

^

+10

j

^

Answer 2

Answer: Hey dude answer is 9.8m/s upward

See the attachment for explanation

Explanation: