Question

a body is projected with the velocity 10i^+20j^ ,find angle of projection

Answer 1

Answer:

See below.

Explanation:

The given velocity vector is,

$\vec{v} = 10\hat{i} + 20\hat{j}$

To get the tan ratio of both the components of the above vector, we use,

$\tan \theta = \frac{\vec{v}_y}{\vec{v}_x} = \frac{20}{10} = 2$

Using the inverse tan function, we get the value for the angle of projection.

$\theta = tan^{-1}( 2 ) = 63.43 ^\circ$