Question

A body is projected with velocity 50 metre per second the ratio of distance travelled in first second of upward motion to first second of downward motion is

Answer 1

Explanation:

The distance covered in first second of upward motion

h=ut-1/2gt²

h=50(1)-1/2×10×(1)²

h=50-5=45m

The distance covered by the body in first second of downward motion

h=ut-1/2gt²

u=0

h=1/2×10×(1)²

h=5

ratio=45/5=9:1

Answer 2

Answer:- 9:1

Explanation:-

h=ut-1/2gt^2

h=50*1-1/2*10*1

h=45m

down ward

h'=ut+1/2gt^2

h'=0+1/2*10

h'=5m

h/h'=45/5m

h:h'=9:1