Question

a body is released from a height above the ground which takes t second to reach the ground the position of the body after t /2 second is

Answer 1

therefore h' = h/4
so, the body would have travelled 'h/4' or position of body from top would be 'h/4'
or position of the body would be '3h/4' from bottom
I have used
$s = u \times t + 1 \div 2 \times a \times {t}^{2}$
where initial velocity i.e. u = 0 , as it is released from the top