A body is released from very large height from the surface of the earth. Its speed just before striking the ground is approximately [Neglecting air resistance] (1) 11.2 km/s (2) 5.6 km/s (3) 3 km/s (4) infinity plz explain
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7y+7g-÷√r please mark me brainlist
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Answer:velocity should be v=R(2*g{(1/R)-(1/r)})^1/2
R= radius of Earth
r= height from which body is released
g= acceleration due to gravity
Explanation: for very large height R is nearly equal to r.
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