Physics, asked by kjsanjith1630, 1 month ago

A body is started from rest and reached the velocity 15m/s in 7sec. Find acceleration.​

Answers

Answered by Anonymous
41

Provided that:

  • Initial velocity = 0 mps
  • Final velocity = 15 mps
  • Time = 7 sec

To calculate:

  • The acceleration

Solution:

  • The acceleration = 2.14 m/s sq.

Using concept(s):

  • Acceleration formula

  • We can also solve this question by using first equation of motion.

Using formula(s):

Acceleration formula:

  • a = (v-u)/t

First equation of motion:

  • v = u + at

Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity and t denotes time taken.

Required solution:

~ By using acceleration formula let us solve this question!

→ a = (v-u)/t

→ a = (15-0)/7

→ a = 15/7

→ a = 2.14 mps sq.

Acceleration = 2.14 mps sq.

~ Also let us use first equation of motion to solve this question!

→ v = u + at

→ 15 = 0 + a(7)

→ 15 = 0 +7a

→ 15 = 7a

→ a = 15/7

→ a = 2.14 mps sq.

Acceleration = 2.14 mps sq.

Know more:

\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf{Three \: equation \: of \: motion}}} \\ \\ \sf \star \: v \: = u \: + at \\ \\ \sf \star \: s \: = ut + \: \dfrac{1}{2} \: at^2 \\ \\ \sf \star \: v^2 - u^2 \: = 2as\end{array}}\end{gathered}

Answered by NewGeneEinstein
85
  • initial velocity=u=0m/s
  • Final velocity=v=15m/s
  • Time=t=7s.

We know

\boxed{\sf Acceleration=\dfrac{v-u}{t}}

\\ \sf\longmapsto Acceleration=\dfrac{15-0}{7}

\\ \sf\longmapsto Acceleration=\dfrac{15}{7}

\\ \sf\longmapsto Acceleration=2.1m/s^2

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