Question

A body is taken to a height equal to radius of the earth and then to a depth equal to radius of the earth.what will be its weight in each case?​

Answer 1

Answer:

when taken r above use then g=GM/(r+r)^2

Answer 2

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Let’s be clear what you mean by a height equal to the radius of the earth. Let R be the radius of the earth. If you are a height R above the surface of the earth, you are a distance of 2R from the center. 3 times the radius of the earth means 3R from the center of the earth. So you go from 2R to 3R so 1/r^2 goes from a factor of 1/4 to 1/9. Further away from the center the weight decreases giving a smaller number so use (1/9)/(1/4) = 4/9. So the 1 N becomes (4/9) N at 3R.

Unless you mean h = R in which case the previous answers would apply where the 1 N becomes (1/9) N at 3R.