A body is thron up with velocity 50m/scalculatly the maximum hight reached and the taken to reach the maximum hight a=10m/s
Answers
Given
velocity (v) = 50 m/s
acceleration = 10 m/s
Required formulas
acceleration = velocity / time
velocity = displacement / time
Answer
acceleration = \frac{velocity}{time} acceleration=
time
velocity
10 = \frac{50}{t} 10=
t
50
\begin{gathered}hence \\ t = \frac{50}{10} \end{gathered}
hence
t=
10
50
hence the time required is 5 seconds
Now
velocity = \frac{displacement}{time} velocity=
time
displacement
Here, displacement is the distance travelled
hence
50 = \frac{s}{5} 50=
5
s
hence
{displacement} = 5 \times 50displacement=5×50
hence
the maximum distance travelled by the object is 250 m
hence your answer should be 250 meter
I hope this answer is helpful to you
if it is then like it and rate it
u=50m/s
g=−10m/s²
The velocity at the highest point will be zero
Thus,
v=0
Height can be calculated as,
v² −u² =2gs
0−2500=−20s
s=125m
Time can be calculated as,
v=u+gt
0=50+(−10)t
t=5sec