Question

A body is thrown horizontally with a velocity √2gh
from the top of a tower of height h. It strikes the
ground level through the foot of the tower at a
distance x from the tower. The value of x is :​

Answer 1

Answer:

2h

Explanation:

kinematics pad lo

Answer 2

Answer:

2h

Explanation:

We have formula in these cases when the body travels in a projectile motion just as like described in the problem.

Formula:

R = u* sqrt(2h/g), where R = distance from tower, u = velocity, h = height of tower, g = acceleration due to gravity.

By substituting the values given in question,

x = sqrt(2gh) * sqrt(2h/g)

x = sqrt(4gh²/g)

x = sqrt(4h²)

x = 2h.

Hope you understood.

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