Question

A body is thrown horizontally with a velocity √2gh from the top of a tower of height h. It strikes the level ground through the foot of the tower at a distance x from the tower. The value of x is : (1) h (2) h/2 (3) 2h (4) 2h/3 ​

Answer 1

Answer:

Correct option is C

Explanation:

2h

Given Horizontal velocity =VH=2gh, 

Vertical velocity=VV=0

Using s=ut+21at2

⇒−h=0−21gt2     ⇒t=g2h

∴ x=VH×t       ⇒x=2gh×g2h=2h