Question

A body is thrown ip with a velocitu 100 m/s. It travels 5m in the last second of its journey. If the same body ia thrown up with a velocity 200m/s. How much distance will it travel in the last second

Answer 1

v
${v }^{2} - {u}^{2} = 2as$
200*200=2*10*S

S=4000m

V=U+aT

200=10*T

T=20s

S=u+g(1/2)(2n-1)

S=200+1/2(2*20-1)

S=200-195

S=5m