Question

A body is thrown up in a lift with a velocity u relative to the lift and the time of flight is found to be the acceleration with which the lift is moving up is

Answer 1

pls find your answer below

Answer 2

Let us assume, the effective acceleration of the body to be G.

Now the equation for the time of flight of the body in the elevator would be given as follows:

Time of flight,

                      $T=\frac { 2u }{ G }$

                      $T=\frac { 2u }{ (g+a) }$

Here g is the gravitational pull and a is the acceleration of the lift.

Rearranging the equation,

                      $(g+a)=\frac { 2u }{ T };$

                      $a=(\frac { 2u }{ T } )–g$