A body is thrown up with a velocity 29.3 ms^-1.The distance travelled by a vertical height
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Assuming the body will fall and terminal velocity is not reached, find out the distance it will travel up by using v² = u²+2as where v² is 0 and a is -9.81 Then use the the same distance again in the same equation to find the ending velocity v v² = u²+2as where u² is 0 and a is 9.81 Note :- Dont mess up the signs of acceleration
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