Question

a body is thrown up with a velocity 50 m/s calculate the maximum reached height and the time taken to reach the maximum height ? (a=10 m/s)

Answer 1

Answer:

u=50m/s

v= 0 ( at max height object will be at rest)

Explanation:

v²+u²= 2as

0+ 50²= 2*10*s

s= 2500/20

s= 125m

v=u+at

t = v-u/a

t= 50-0/10

t= 5 sec