Question

a body is thrown upward with a speed of 19.6m/s.find its speed after 2 seconds

Answer 1

V=u+at

Where v is final velocity and

u is initial velocity

a=acceleration =g,acceleration due to gravity

t is time then,

V=19.6+(_9.8)×2

V=19.6_19.6

V=0

Answer 2

Answer:

A body is thrown upward with a speed of 19.6m/s. The speed after 2 seconds will be $0 m/s$

Explanation:

• From the question,

       The initial speed of the body = $19.6m/s$

       The time is taken = $2 s$

• We can solve this problem using the first equation of motion.

        It is given by,

        $V = u+at$    ...(1)

       Where $V$is the final velocity of the body, $u$ is the initial velocity, $a$ is the acceleration due to gravity, and $t$is the time taken by the body.

• since the body is thrown upwards.

        $a = -g$

        We know g is the acceleration due to gravity

        $g= 9.8m/s^2$

Substitute these values into equation (1)

$V = 19.6-(9.8\times 2)$

    $=19.6-19.6 =0\ m/s$