Math, asked by masterajaysoni, 1 year ago

answer pleaseeeeeeeeeeeeee

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Answered by vijyakrishnani
0

 \frac{1}{2} x +  \frac{1}{3} x =  \frac{1}{5} x \\ \frac{3x + 2x}{6}  =  \frac{1}{5} x \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \ \:  \: .......(after \: takimg \: lcm \: in \: lhs) \\  \frac{5x}{6}  =  \frac{1}{5} x \\  \frac{5x}{6}  -  \frac{x}{5}  = 0 \\  \frac{25x - 6x}{30}  = 0 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ...........(after \: taking \: lcm \: on \: lhs) \\  \frac{19x}{30}  = 0 \\ 19x = 0 \times 30 \\ 19x = 0 \\ x = \frac{0}{19}  \\ x = 0

masterajaysoni: after first lcm why had you done - explain
vijyakrishnani: added the numerator terms......
vijyakrishnani: then moved the rhs term to lhs to subtract it from term present in lhs
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