Question

A body is thrown vertically up from the top of a building with a velocity of 10m/s . let reaches the ground in 5s. Find the height of the building and velocity with which the body reaches the ground .[g=10m/s^2]​

Answer 1

Answer:

when it goes up

v^2=u^2-2as

0=100-2×10×s

20s=200

s=5m

it reaches ground after 5 second

v=u-at (v=0)

u=at

10=10×t

t=1second

s=ut+1/2at^2

s=0×u+1/2×10×16

=0×4+1×10×8

=75m

g=10m/s^2 & h=75m

Explanation:

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