यदि x/y +y/x = -1, (x=not 0
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x/y + y/x = -1
or, (x²+y²)/xy = -1
or, x²+y² = -xy
or, x²+y²+xy = 0.
or, (x² + xy + y²) = 0.
now,
x³-y³
= (x-y) (x²+xy+y²)
= 0. [ as (x²+xy+y²) = 0. ]
please mark me brainlist
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