Question

A body is thrown vertically up from the top of a tower with a velocity of 2 m/s. Its velocity after two seconds

Answer 1

Answer:

u=2

a= -10m/s^2

t=2 sec

v=u+at

v= 2-20

v=-18m/s

ball will fall downward with 18m/s

Answer 2

Answer:

Explanation:

Given

u=2m/s

t=2sec

the velocity of vertically project body

v=u-gt

v=2-9.8*2

v=17.6m/s