Question

A body is thrown vertically up from the top of cliff with a velocity 9.8 m/s^2.

It reaches the bottom of the cliff after 22 s. Find the height of the cliff.​

Answer 1

Answer:

not 100 percent sure but I think40.06 m can be right answer

Answer 2

$\text{Let the height of the cliff be x m}$

$Acceleration\:due\:to\:gravity = 9.8 ms^{-2}$

$Time\:taken\:to\:reach\:the\:ground = 22sec$

$\red{\boxed{h = \dfrac{1}{2}gt^{2}}}$

$\blue{\boxed{h = \dfrac{1}{2} × 9.8 × 22^{2}}}$

$\blue{\boxed{h = \dfrac{1}{2} × 9.8 ×484 }}$

$\blue{\boxed{h = 2371.6}}$

Hope it helps you