Question

Find the roots of the following quadratic equation 2/5x^2-x-3/5=0​

Answer 1

Answer:

Click on the pic you will get the answer....

Answer 2

Step-by-step explanation:

$(2 \div 5)x {}^{2} - x - (3 \div 5) = 0$

To eliminate the fraction we would take the LCM of denominators of all the terms and multiply with each of them

LCM = 5

Multiplying 5 with each of them

$2x {}^{2} - 5x - 3 = 0$

$2x {}^{2} - 6x + 1x - 3 = 0 \\ 2x(x - 3) + 1( x - 3) = 0 \\ (x - 3)(2 x + 1) = 0$

Hence

x – 3 = 0

x = 3

or

2x + 1 = 0

2x = – 1

x = –1 / 2