A body is thrown vertically upward in such a way that height at 8th second and 12th second is same then the velocity with which body was thrown is;
Answers
Answered by
0
Answer:
Explanation:
that means time of ascent = 10m/s
v=u+at
0=u-98
u=98 m/s
it can be done in another way
v=u+at
here time t1+ (t2-t1 / 2 )
time = t1+t2 / 2
where t1 and t2 are times when it passes through same point
time = 10
u=98 m/s
Similar questions