A body is thrown vertically upward with 45m/s.distance travelled by the body in 5th sec is (g=10m/s²).
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A body projected upwards decelerate s due to the force of gravity.
Therefore the equation for getting the distance is :
S=ut-1/2at2
S represents the distance, u represents the initial speed, the the time and a the acceleration due to gravity.
Substituting the values for each initial we have:
S=45×5-(10×0.5^2)/2=225-1.25=223.75m
The distance is 223.75
Therefore the equation for getting the distance is :
S=ut-1/2at2
S represents the distance, u represents the initial speed, the the time and a the acceleration due to gravity.
Substituting the values for each initial we have:
S=45×5-(10×0.5^2)/2=225-1.25=223.75m
The distance is 223.75
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