Question

A body is thrown vertically upward with a speed of 30 metre per second how high will it rise will it rise please answer dena

Answer 1

Answer:

Given:

An object is thrown upwards vertically with an initial velocity of 30 m/s.

To find:

Height to which the object will rise.

Formulas used:

v² = u² + 2as

where v=> final Velocity, u=> initial Velocity , a => acceleration and

s =>distance.

Calculation:

Final Velocity at max height will be zero.

v² = u² + 2as

=> 0² = (30)² + 2 × (-10) × s

=> 0 = 900 - 20s

=> 20s = 900

=> s = 45 metres.

Height = 45 metres.

Answer 2

$\huge\mathfrak\green{\underline{Answer:45\:m}}$

$\rule{100}2$

It is given that, A boy is thrown vertically upward with a velocity of 30 m/s, i.e

u = 30 m/s

It's final velocity will be 0 ( body will be a maximum height ) , i.e v = 0

g = 10 m/s² or 9.8 m/s ( to make  calculation easier, we often take 10 m/s ).

It is stated ' body is thrown vertically upward ' it means it is moving against gravitation. So, It's negative acceleration.

g = - 10 m/s²

Now,

From kinematical equation ( 3 ),

$\sf{\red{v^2}\:-\:{u}^2\:=\:2{g}{s}}$

Put the given values in the equation. we get,

$\sf 0^2 - (30)^2=2(-10)\times {s}$

$\sf\implies {-900}=20\times {s}$

$\sf\implies {s}=\dfrac{-900}{-20}$

$\sf\therefore {s}=45$

Hence,

It will rise 45 m from the ground.

$\rule{200}2$