Question

A body is thrown vertically upward with speed 25 m/s. The distance covered by the body in 3rd second is
O 1.25 m
O 2.5 m
O Zero
O 5 m​

Answer 1

Answer:

HERE IS YOUR ANSWER

Explanation:

we know that distance covered by an object in nth second, s = u + a(2n-1)/2

s = 25 + (-9.8)(2*3–1)/2

s = 25 - 9.8*5/2

s = 25 - 24.5

s = 0.5 m

Answer 2

Explanation:

g=-10

s=ut+1/2at^2

s=25×3+1/2(-10)3^2

s=75-30

s=45m