sorry this is my not question but this is my friend question I wrote his answer.please notes
polynomia (x−1)(x−2)(x−3)(x−4)(x-1)(x-2)(x-3)(x-4)
Set (x−1)(x−2)(x−3)(x−4)(x-1)(x-2)(x-3)(x-4) equal to 00.
(x−1)(x−2)(x−3)(x−4)=0(x-1)(x-2)(x-3)(x-4)=0
Solve for xx.
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If any individual factor on the left side of the equation is equal to 00, the entire expression will be equal to 00.
x−1=0x-1=0
x−2=0x-2=0
x−3=0x-3=0
x−4=0x-4=0
Set x−1x-1 equal to 00 and solve for xx.
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x=1x=1
Set x−2x-2 equal to 00 and solve for xx.
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x=2x=2
Set x−3x-3 equal to 00 and solve for xx.
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x=3x=3
Set x−4x-4 equal to 00 and solve for xx.
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x=4x=4
The final solution is all the values that make (x−1)(x−2)(x−3)(x−4)=0(x-1)(x-2)(x-3)(x-4)=0 true.
x=1,2,3,4x=1,2,3,4

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