Math, asked by faisalahmedsoormo200, 9 months ago

sorry this is my not question but this is my friend question I wrote his answer.please notes

polynomia (x−1)(x−2)(x−3)(x−4)(x-1)(x-2)(x-3)(x-4)

Set (x−1)(x−2)(x−3)(x−4)(x-1)(x-2)(x-3)(x-4) equal to 00.

(x−1)(x−2)(x−3)(x−4)=0(x-1)(x-2)(x-3)(x-4)=0

Solve for xx.

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If any individual factor on the left side of the equation is equal to 00, the entire expression will be equal to 00.

x−1=0x-1=0

x−2=0x-2=0

x−3=0x-3=0

x−4=0x-4=0

Set x−1x-1 equal to 00 and solve for xx.

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x=1x=1

Set x−2x-2 equal to 00 and solve for xx.

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x=2x=2

Set x−3x-3 equal to 00 and solve for xx.

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x=3x=3

Set x−4x-4 equal to 00 and solve for xx.

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x=4x=4

The final solution is all the values that make (x−1)(x−2)(x−3)(x−4)=0(x-1)(x-2)(x-3)(x-4)=0 true.

x=1,2,3,4x=1,2,3,4



Answers

Answered by druthishetty07
0

for exam...................

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