Question

A body is thrown vertically upward with velocity of 200m / Sec. How high will it rise when g = 10 m/Sec?​

Answer 1

Answer:

14 m/s

Maximum height  h=10 m/s

At maximum height,   v=0

Let the initial velocity be u.

Acceleration   a=−g=−9.8 m/s  

2

 

∴  0−u  

2

=2(−9.8)(h)

⟹ u=  

2gh

​  

=  

2×9.8×10

​  

=14 m/s

Explanation:

Answer 2

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When a body is thrown vertically upwards, at the highest point only velocity is zero because the acceleration due to gravitational force is acting downward continuously and that is the reason for velocity being zero at the highest point, hence velocity is zero because of the acceleration.

The kinematics equations are,

v=u+at

v2=u2+2as

s=12(v+u)t

s=ut+12at2

u -initial velocity

v- final velocity

t-time

a-acceleration

We assume that there is no air resistance. Otherwise, we will need to introduce some proportionality constant. Gravity is the only acceleration acts on the object.

The initial motion of the object is upwards and gravity is acting downwards. Hence, by convention we have,

a=−g

Its numerical value is 9.81 but I will use 10 m2/s for convenience.

The most suitable equation for the height of the object is

v2=u2−2gs

When the object reached its peak it will have zero speed or velocity. Hence the final velocity is 0.

v=0

u=20

0=(20)2−2(10)s

s=20m

We can now see the time the object is at its peak

v=u+at

0=20–10t

t=2s