Question

A body is thrown vertically upwards and rises to a height of 45 m calculate total time for which body remains in air and time taken by the object to reach the its highest point and also calculate the velocity with which the object is thrown upward

Answer 1

Answer:

given,

distance travaled, s =45 m

final velocity =0 m/s

g=-9.8m/s²

by using formula

v²- u²= 2gs

put the value u will get the answer

then, u is the velocity at which the body is thrown upward

now,

v= u+gt

t=v-u/g

put the value u will get the answer

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