Question

A body is thrown vertically upwards and rises to a height of 45 m calculate total time for which body remains in air and time taken by the object to reach the its highest point and also calculate the velocity with which the object is thrown upward

Answer 1

Step-by-step explanation:

ANSWER

In this case,

v

2

−u

2

=2(−g)h

when h=h

max

;

v=0

so, u=

2×g×h

u=14

For time t;

v=u−gt;

so, t=14/9.8 = 14.3m/s

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Answer 2

Answer:

14.3m/s

Step-by-step explanation:

In this case,

v

2

−u

2

=2(−g)h

when h=h

max

;

v=0

so, u=

2×g×h

u=14

For time t;

v=u−gt;

So, t=14/9.8 = 14.3m/s