A body is thrown vertically upwards from height of buildin 21 m with initial velocity 14 m\s find the velocity striking the ground
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5
v^2 -u^2 = 2as
intial will be 0 as body go up and the stop for few second and came down due to influence of gravity .
v^2= 21 x 2 x 9.8
v = 6.4 m/s
intial will be 0 as body go up and the stop for few second and came down due to influence of gravity .
v^2= 21 x 2 x 9.8
v = 6.4 m/s
Ravishkumar11:
what is the time taken to strike the ground
no need of time
cab u find the time when it will strike
Answered by
3
v= 0
u= 0 as we are throwing the object upward it will stop . and again gain velocity due to g
g=9.8m/^2
h=21
using formula
v^2+u^2=2as
v^2=2×9.8×21
v^2=41.16
v=6.415m/s
u= 0 as we are throwing the object upward it will stop . and again gain velocity due to g
g=9.8m/^2
h=21
using formula
v^2+u^2=2as
v^2=2×9.8×21
v^2=41.16
v=6.415m/s
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