A body is thrown vertically upwards with an initial velocity of 200mpersecond. find time taken by it to reach the maximum height and velocity after 10 seconds
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You didn’t give units for your velocity, but I’ll assume meters per second, since 9.8 is the acceleration of gravity in those units.
So gravity removes 9.8 m/s of upward velocity each second, so your body will travel upward for one second. During that time its velocity is not constant - it will be slowing down continuously as it moves upward. The proper way to do the calculation is as follows:
d2xdt2=−9.8d2xdt2=−9.8
dxdt=−9.8t+v0dxdt=−9.8t+v0
x=−4.9∗t2+v0t+x0x=−4.9∗t2+v0t+x0
In your problem v0 (the initial velocity) is 9.8,
So gravity removes 9.8 m/s of upward velocity each second, so your body will travel upward for one second. During that time its velocity is not constant - it will be slowing down continuously as it moves upward. The proper way to do the calculation is as follows:
d2xdt2=−9.8d2xdt2=−9.8
dxdt=−9.8t+v0dxdt=−9.8t+v0
x=−4.9∗t2+v0t+x0x=−4.9∗t2+v0t+x0
In your problem v0 (the initial velocity) is 9.8,
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